9.8t^2=1

Solution for 9.8t^2=1 equation:

9.8t^2=1

We move all terms to the left:

9.8t^2-(1)=0

a = 9.8; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·9.8·(-1)
Δ = 39.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{39.2}}{2*9.8}=\frac{0-\sqrt{39.2}}{19.6}
=-\frac{\sqrt{}}{19.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{39.2}}{2*9.8}=\frac{0+\sqrt{39.2}}{19.6}
=\frac{\sqrt{}}{19.6}
$